Pattern Printing

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WHY PROGRAMMING?

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                                                                                 Following are the reasons why we should learn programming : 1>"Because it makes you think". 2>"It makes you understand what technology really means ." 3>"It is just like a superpower that any hero has and can be achieved by any one of us." By programming, we can make a machine (robots etc.) to do a work what we want from them to do by just giving instructions. example-instruction given to a robot to walk.  "you need not have to be a genius  but a determinant person"                                               " programmers of today are the wiza...
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Series code 2

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CODE NO:- 06 Q)Find the no. for a user given position for this series  0,0,2,1,4,2,6,3,8,4,…     For example: (1) At position 4 you should get no. :1                             (2) At position 9 you should get no. :8 #LOGIC According to the given series, we can conclude that : 1) At even indexes, we are having a series which starts from 0 and gets incremented by (+2) . 2) At odd indexes, we are having a series which starts from 0 and gets incremented by (+1) . NOTE : Here we are considering 0 as starting index. #Program  (In C++): #include<iostream> using namespace std; int main() { int n,t; cout<<"\n enter the position :"; cin>>n; if(n%2==0) { n=n/2; t=(n-1); cout<<"The no. at given position is:"<<t; } else { n=n/2+1; t=(n-1)*2; cout<<"The...
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Pattern Printing coding 7

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CODE NO:- 09 Print the below pattern #LOGIC Take a variable and assign it with value n+2 and print this value using the inner loop whereas in the outer loop decrement the value by 1. Here n is the no. of entered rows whereas n+2 is the first element of the pattern. ex: if n=4 then n+2 result 6. #Program( In C): In    C language we use  ' // '  for Single line comment and /*---*/ for multi line comment #include<stdio.h> // header file for i/p and o/p int main() { int n,i,j,k,a; printf("\n enter the no.of rows:"); scanf("%d",&n); a=n+2; for(i=0;i<n;i++) {           for(k=0;k<n-i;k++)   { printf("%d ",a);           }           a--;// decrementing value by 1 printf("\n"); } return 0; } We got this output by using DEV C++ (IDE) Link: For ot...
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