Pattern Printing coding 12

-
//If you are visiting this post in mobile then, please use desktop site mode //   

 CODE NO:- 21
Print the below pattern
                                                                                                                                                   



#LOGIC
Take two variables and assign it with value (n*n)-(n-1) and 0(zero)  here n means the no. of entered rows and (n*n)-(n-1) is the first element of the pattern.
ex: if n is 4 then (n*n)-(n-1) results 13. 
Now copy the value (n*n)-(n-1) in other variable and increment it by 1 in the inner loop whereas in the outer loop decrement it by value n. Proceed in the same manner to print the pattern.

#Program( In C):
In  C language we use  ' // '  for Single line comment and /*---*/ for multi line comment

#include<stdio.h> // header file for i/p and o/p
int main()
{
int i,j,a,n,b=0;;
printf("\n enter the no. of rows:");
scanf("%d",&n);
a=(n*n)-(n-1);
for(i=0;i<n;i++)
{
b=a;
for(j=0;j<n;j++)
{
printf("%3d",b++);// %3d is used to display the pattern correctly(spacing)
}// b++ is post increment
a=a-n;
printf("\n");
}
/* %3d is a format specifier where
% means "print the variable here"
3 means "use at least 3 spaces to display, padding as needed"
d means integer
putting above sentences together we can say that:
"print an integer, taking minimum 3 spaces" */
return 0;
}
We got this output by using DEV C++ (IDE)
        
Link: For other pattern printing problems                 

Comments

Post a Comment

Popular posts from this blog

WHY PROGRAMMING?

-
Image
                                                                                 Following are the reasons why we should learn programming : 1>"Because it makes you think". 2>"It makes you understand what technology really means ." 3>"It is just like a superpower that any hero has and can be achieved by any one of us." By programming, we can make a machine (robots etc.) to do a work what we want from them to do by just giving instructions. example-instruction given to a robot to walk.  "you need not have to be a genius  but a determinant person"                                               " programmers of today are the wiza...
Read more

Series code 2

-
Image
CODE NO:- 06 Q)Find the no. for a user given position for this series  0,0,2,1,4,2,6,3,8,4,…     For example: (1) At position 4 you should get no. :1                             (2) At position 9 you should get no. :8 #LOGIC According to the given series, we can conclude that : 1) At even indexes, we are having a series which starts from 0 and gets incremented by (+2) . 2) At odd indexes, we are having a series which starts from 0 and gets incremented by (+1) . NOTE : Here we are considering 0 as starting index. #Program  (In C++): #include<iostream> using namespace std; int main() { int n,t; cout<<"\n enter the position :"; cin>>n; if(n%2==0) { n=n/2; t=(n-1); cout<<"The no. at given position is:"<<t; } else { n=n/2+1; t=(n-1)*2; cout<<"The...
Read more

Pattern Printing coding 7

-
Image
CODE NO:- 09 Print the below pattern #LOGIC Take a variable and assign it with value n+2 and print this value using the inner loop whereas in the outer loop decrement the value by 1. Here n is the no. of entered rows whereas n+2 is the first element of the pattern. ex: if n=4 then n+2 result 6. #Program( In C): In    C language we use  ' // '  for Single line comment and /*---*/ for multi line comment #include<stdio.h> // header file for i/p and o/p int main() { int n,i,j,k,a; printf("\n enter the no.of rows:"); scanf("%d",&n); a=n+2; for(i=0;i<n;i++) {           for(k=0;k<n-i;k++)   { printf("%d ",a);           }           a--;// decrementing value by 1 printf("\n"); } return 0; } We got this output by using DEV C++ (IDE) Link: For ot...
Read more