Pattern Printing coding 14

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CODE NO:- 23
Print the below pattern


#LOGIC
Using two inner loop print the first half of the pattern.

Using another two inner loop print the second half of the pattern.
For example:  if entered no.of rows are 4 then the first half will contain 4 rows and another half will contain 3 rows.

#Program( In C):
In  C language we use  ' // '  for Single line comment and /*---*/ for multi line comment

#include<stdio.h>// header file for i/p and o/p
int main()
{
int i,j,a=0,b,n,k;
printf("\n enter no. of rows:");
scanf("%d",&n);
for(i=0;i<n;i++)// loop for printing the upper half of the pattern
{
for(j=0;j<=i;j++)
{
printf("*");
}
printf("\n");
}
for(i=0;i<n-1;i++)// loop for printing the lower half of the pattern
{
for(j=0;j<n-1-i;j++)
{
printf("*");
}
printf("\n");
}
return 0;
}

We got this output by using DEV C++ (IDE)


Link: For other pattern printing problems

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