Series Printing coding 3
CODE NO:- 15
Q)Write a program to display the sequence 1,2,2,4,8,32,256.....
#LOGIC
If you observe this series carefully you will find this is somewhat same as the Fibonacci series with minute change instead of "+" between the two previous terms we are having "*".
NOTE: Considering starting index as 0 (zero).
For example: we got 2 by multiplying 1 and 2 i.e we got 2nd term by multiplying 1st term and 0th term.
#Program (In C++):
In C++ language we use ' // ' for Single line comment and /*---*/ for multi line comment
#include<iostream> // header file for i/p and o/p
using namespace std;
int main()
{
int n,re,a=1,b=2,i;
cout<<"\n enter the value of n (no. of terms):";
cin>>n;
cout<< a <<" "<< b ;
for(i=2;i<n;i++) // here i=2 because first two terms we had already printed (a,b)
{
re=a*b;
cout<<" "<<re ;
a=b;
b=re;
}
return 0;
}
We got this output by using DEV C++ (IDE)
Link: For other series printing problems
Q)Write a program to display the sequence 1,2,2,4,8,32,256.....
#LOGIC
If you observe this series carefully you will find this is somewhat same as the Fibonacci series with minute change instead of "+" between the two previous terms we are having "*".
NOTE: Considering starting index as 0 (zero).
For example: we got 2 by multiplying 1 and 2 i.e we got 2nd term by multiplying 1st term and 0th term.
#Program (In C++):
In C++ language we use ' // ' for Single line comment and /*---*/ for multi line comment
#include<iostream> // header file for i/p and o/p
using namespace std;
int main()
{
int n,re,a=1,b=2,i;
cout<<"\n enter the value of n (no. of terms):";
cin>>n;
cout<< a <<" "<< b ;
for(i=2;i<n;i++) // here i=2 because first two terms we had already printed (a,b)
{
re=a*b;
cout<<" "<<re ;
a=b;
b=re;
}
return 0;
}
We got this output by using DEV C++ (IDE)
Link: For other series printing problems
Beta hindi ka kuch b nahi hai.maths k liye mera mun nahi hota
ReplyDeleteVery nice
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